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  1. Edward, thanks for your valuable input. It is...

    Edward,

    thanks for your valuable input. It is great to have this forum to get your questions answered.
    It has been a great resource for the thesis for a first year team.
    Somebody suggested in...
  2. Hi Thijs, I am not yet in Stuttgart, although...

    Hi Thijs,
    I am not yet in Stuttgart, although already have my dorm room and will start there in 2 weeks on the 7. of April for the summer semester.
    I was referencing to my former college, a small...
  3. Using the combined acceleration of 1,06 G gives...

    Using the combined acceleration of 1,06 G gives following forces:

    X: 835,4 N
    Y: 1090,1 N
    Z: 1610,5 N

    These should be more realistic.
  4. Hi Tim! I didn't use the coefficient of 0,9...

    Hi Tim!

    I didn't use the coefficient of 0,9 during the initial calculations for the first post. After Edward asked what friction coefficient would be needed to get
    to my initial results, I looked...
  5. Hello Edward! Assuming the tire friction...

    Hello Edward!

    Assuming the tire friction coefficent is 0,9. That means if my tire has 2168 N normal force, it is capable of 1951,2 N longitudinal breaking force.
    This would suggest that my number...
  6. Calculating tire forces under combined braking and lateral acceleration for 1 wheel

    Hi Guys,

    putting the last touches on my bachelor thesis about the design of a FSAE suspension system
    for the team that maybe will exist in the future of my former college.

    I am going through...
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