Edward,
thanks for your valuable input. It is great to have this forum to get your questions answered.
It has been a great resource for the thesis for a first year team.
Somebody suggested in...
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Type: Posts; User: MP4/4
Edward,
thanks for your valuable input. It is great to have this forum to get your questions answered.
It has been a great resource for the thesis for a first year team.
Somebody suggested in...
Hi Thijs,
I am not yet in Stuttgart, although already have my dorm room and will start there in 2 weeks on the 7. of April for the summer semester.
I was referencing to my former college, a small...
Using the combined acceleration of 1,06 G gives following forces:
X: 835,4 N
Y: 1090,1 N
Z: 1610,5 N
These should be more realistic.
Hi Tim!
I didn't use the coefficient of 0,9 during the initial calculations for the first post. After Edward asked what friction coefficient would be needed to get
to my initial results, I looked...
Hello Edward!
Assuming the tire friction coefficent is 0,9. That means if my tire has 2168 N normal force, it is capable of 1951,2 N longitudinal breaking force.
This would suggest that my number...
Hi Guys,
putting the last touches on my bachelor thesis about the design of a FSAE suspension system
for the team that maybe will exist in the future of my former college.
I am going through...